Q.
The four capacitors, each of 25 $\mu$F are connected as shown in figure. The DC voltmeter reads 200 V. the change on each plate of capacitor is
A) $\pm 2 \times 10^{- 3}$C
B) $\pm 5 \times 10^{- 3}$C
C) $\pm 2 \times 10^{- 2}$C
D) $\pm 5 \times 10^{- 2}$C
Explanation
(b) Charge on each plate of each capacitor
$Q = \pm CV = \pm 25 \times 10^{- 6} \times 200$
$= \pm 5 \times 10^{- 3}C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.