Q. The potential at a point P which is forming a corner of a square of side 93mm with charges, $\mathcal{Q}_{1} = 33$ nC,$\mathcal{Q}_{2} = - 51\ nC,\ \mathcal{Q}_{3} = 47nC$ located at the other three corners is nearly

A) 16kV
B) 4kV
C) 400V
D) 160V
Explanation

(b) $V = \frac{1}{4\pi\varepsilon_{0}}\left( \frac{\mathcal{Q}_{1}}{r_{1}} + \frac{\mathcal{Q}_{2}}{r_{2}} + \frac{\mathcal{Q}_{3}}{r_{3}} \right)$
$= \frac{1}{4\pi\varepsilon_{0}}\left( \frac{33 \times 10^{- 9}}{93 \times 10^{- 3}} - \frac{51 \times 10^{- 9}}{\sqrt{2} \times 93 \times 10^{- 3}} + \frac{47 \times 10^{- 9}}{93 \times 10^{- 3}} \right)$
$= \frac{1}{4\pi\varepsilon_{0}} \times \frac{10^{- 9}}{93 \times 10^{- 3}}\left( 33 - \frac{51}{\sqrt{2}} + 47 \right)$
$\approx 4 \times 1000\ V = 4\ kV$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.