Q.
Each capacitor shown in figure is $2\ \mu F.\ $Then the equivalent capacitance between points $A\ and\ B$ is
A) 2 $\mu F$
B) 4 $\mu F$
C) 6 $\mu F$
D) 8 $\mu F$
Explanation
(a) The figure is a balanced Wheatstone bridge, so diagonal capacitor will be ineffective.
So, the equivalent circuit will be as shown in the figure.
[image:2_image99.emf]
Equivalent capacitance of upper arms in series
$\ \ \ \ \ C_{1} = \frac{2 \times 2}{2 + 2} = 1\mu F$
Similarly, for lower arm
$\ \ \ \ \ \ C_{2} = 1\mu F$
$\therefore\ \ C_{AB} = C_{1} + C_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ = 1 + 1 = 2\mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.