Three capacitors of capacitance $1\ \mu F,\ 2\ \mu F\ and\ 4\mu F$ are connected first in a series combination, and then in a parallel combination. The ratio of their equivalent capacitance will be

Question

Dr. Abubacker · Accepted Answer

(c) In series combination,
$\ \ \ \ \ \frac{1}{C_{1}} = \frac{1}{1} + \frac{1}{2\ } + \frac{1}{4} = \frac{4 + 2 + 1}{4} = \frac{7}{4}$
$\Rightarrow \ C_{1} = \frac{4}{7}\mu F$
In parallel combination,
$\ \ \ \ C_{2} = 1 + 2 + 4 = 7\mu F$
$	herefore\frac{C_{1}}{C_{2}} = \frac{4/7}{7} = \frac{4}{49}$

Q. Three capacitors of capacitance $1\ \mu F,\ 2\ \mu F\ and\ 4\mu F$ are connected first in a series combination, and then in a parallel combination. The ratio of their equivalent capacitance will be

Explanation

Reviewed by Dr. Abubacker

Want more practice?