A slab of copper of thickness $b$ is inserted in between the plates of parallel plate capacitor as shown in figure. The separation between the plates is $d$ if $b = d/2$, then the ratio of capacities of capacitors after and before inserting the slab will be [image:2_image23.emf]

Question

Dr. Abubacker · Accepted Answer

(b) $C = \frac{A\varepsilon_{0}}{d}$
After inserting the slab
$C^{'} = \frac{A\varepsilon_{0}}{(d - b)} = \frac{A\varepsilon_{0}}{d - \frac{d}{2}}$
$C' = \frac{2A\varepsilon_{0}}{d}$ $\ \ 	herefore\ \frac{C^{'}}{C} = \frac{2}{1}$

Q. A slab of copper of thickness $b$ is inserted in between the plates of parallel plate capacitor as shown in figure. The separation between the plates is $d$ if $b = d/2$, then the ratio of capacities of capacitors after and before inserting the slab will be

Explanation

Reviewed by Dr. Abubacker

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