Q. In the case of a charged metallic sphere, potential (V) changes with respect to distance(S) from the centre as

A) [image:2_image24.emf]
B) [image:2_image25.emf]
C) [image:2_image26.emf]
D) [image:2_image27.emf]
Explanation

(c) If we take a charge from one point to another inside a charged spherical shell, then no work will be done. This means that inside a spherical charge the potential at all points is the same and its value is equal to that on the surface, that is
[image:2_image103.emf]
$V = \frac{1}{4\pi\varepsilon_{0}}\frac{q}{R}\ volt$
Also outside the metallic sphere
$V = \frac{1}{4\pi\varepsilon_{0}}\ .\frac{q}{r}$
$V \propto \frac{1}{r}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.