Q. The electrostatic potential energy between proton and electron separated by a distance 1Å is
A) 13.6eV
B) 27.2eV
C) 14.4eV
D) 1.44eV
Explanation
(c) $U = \frac{1}{4\pi\varepsilon_{0}}\frac{q_{1}q_{2}}{r}$
$\therefore U = \frac{9 \times 10^{9} \times \left( 1.6 \times 10^{- 19} \right)\left( - 1.6 \times 10^{- 19} \right)}{10^{- 10}}$
$= - 9 \times 10^{9} \times 1.6 \times 10^{- 19} \times 10^{10}eV$
$= - 14.4eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.