Q.
The variation of potential V with distance $x$ from a fixed point charge is shown in figure. The electric field strength between $x = 0.1\ $m and 0.3 m is
A) $+ 0.4\ Vm^{- 1}$
B) $- 0.4\ Vm^{- 1}$
C) $+ 10\ Vm^{- 1}$
D) $- 10\ Vm^{- 1}$
Explanation
(c) $E = - \frac{dV}{dr} = - \frac{(1 - 3)}{0.3 - 0.1}Vm^{- 1} = 10\ V\ m^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.