Q. If the electric flux entering and leaving an enclosed surface respectively is $\phi_{1}$ and $\phi_{1}$, then, charge enclosed in closed surface is
A) $\frac{\phi_{2} - \phi_{1}}{\varepsilon_{0}}$
B) $\frac{\phi_{1} + \phi_{2}}{\varepsilon_{0}}$
C) $\frac{\phi_{1} - \phi_{2}}{\varepsilon_{0}}$
D) $\varepsilon_{0}(\phi_{2} - \phi_{1})$
Explanation
(d) Net electric flux of surface
$\left( \phi_{2} - \phi_{1} \right) = \frac{1}{\varepsilon_{0}}(q) \Rightarrow q = \varepsilon_{0}\left( \phi_{2} - \phi_{1} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.