Q. Three capacitors of capacitance $C(\mu F)$ are connected in parallel to which a capacitor of capacitance $C$ is connected in series. Effective capacitance is 3.75, then capacity of each capacitor is
A) 4 $\mu F$
B) 5 $\mu F$
C) 6 $\mu F$
D) 8 $\mu F$
Explanation
(b) The effective capacitance of three capacitor connected in parallel=$3C$
When $3C$is connected in series to $C$
$C_{resul} = \frac{3C \times C}{3C + C} = 3.75$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C = 5\mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.