Q.
Six charges, three positive and three negative of equal magnitude are to be placed at the vertices of a regular hexagon such that the electric field at O is double the electric field when only one positive charge of same magnitude is placed at $R.$ which of the following arrangements of charges is possible for P, Q, R, S, T and U respectively?
A) $+ , - , + , - , - , +$
B) $+ , - , + , - , + , -$
C) $+ , + , - , + , - , -$
D) $- , + , + , - , + , -$
Explanation
(d) The net field at $O.$
$E = 2{\overrightarrow{E}}_{R},\ when\ \ {\overrightarrow{E}}_{p} + {\overrightarrow{E}}_{s} = \overrightarrow{0},{\overrightarrow{E}}_{Q} + {\overrightarrow{E}}_{T} = \overrightarrow{0}\ \ and\ \ {\overrightarrow{E}}_{R}$=${\overrightarrow{E}}_{U}\ along\ ROU\ $diriction. It is possible in arrangement of (d) as shown in a joining figure.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.