Q.
Charges $+ 2Q$ and $–Q$ are placed as shown is figure. The point at which electric filed intensity is zero will be
A) Somewhere between $–Q\ $and $+ 2Q\ $
B) Somewhere on the left of $–Q\ $
C) Somewhere on the right of $+ 2Q$
D) Somewhere on the right bisector of line joining $–Q\ $and $+ 2Q.$
Explanation
(b) For neutral point ${\overrightarrow{E}}_{A} + {\overrightarrow{E}}_{B} = \overrightarrow{0}\ \ or\ \ {\overrightarrow{E}}_{A} = - {\overrightarrow{E}}_{B}.$ It is possible, in present problem, only at a point somewhere on the left of$- Q$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.