Q. Three capacitors of capacitances 4 $\mu$F, 6$\ \mu$F and 12 $\mu$F are connected first in series and then in parallel. What is the ratio of equivalent capacitance in the two cases?

A) 2 : 3
B) 1 : 11
C) 11 : 1
D) 1 : 3
Explanation

(b) $\frac{1}{C_{s}} = \frac{1}{4} + \frac{1}{6} + \frac{1}{12} = \frac{3 + 2 + 1}{12} = \frac{6}{12} = \frac{1}{2}$
$C_{s} = 2\ \mu F$
$C_{p} = 4 + 6 + 12 = 22\ \mu F$
$\frac{C_{s}}{C_{p}} = \frac{2}{22} = \frac{1}{11}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.