(a) $r_{b} - r_{a} = 1mm = 10^{- 3}m\ $
From $\ \ \ \ \ C = \frac{4\pi\varepsilon_{0}r_{a}r_{\begin{array}{r}
b \\
\
\end{array}}}{r_{b} - r_{a}}$
$10^{- 6} = \frac{1\left( r_{b} - 10^{- 3} \right)r_{b}}{9 \times 10^{9}(10^{- 3})}$
$r_{b}^{2} = 9,\ r_{b} = 3m$