(a) Number of capacitors to be connected in series
$V = \frac{valtage\ rating\ required}{voltage\ rating\ of\ given\ capacitor\ } = \frac{700}{200} = 3.5ie,\ 4$
$C_{eq} = \frac{10}{4} = 2.5\mu F$
Number of rows required
$= \frac{capacitor\ required}{capacity\ of\ each\ row\ } = \frac{10}{2.5} = 4$
$\therefore$ total number of capacitors required $= 4 \times 4 = 16$