Q.
The equivalent capacitance of the combination of three capacitors, each of capacitance C shown in figure between points A and B is
A) $\frac{C}{2}$
B) $\frac{3C}{2}$
C) $\frac{1}{3C}$
D) 2C
Explanation
(d) In the arrangement shown both plates of capacitors $C_{3}$ are joined to point $B.$ Hence, it does not act as a capacitor and is superfluous. Now $C_{1}$ and $C_{2}$ are in parallel, hence $C_{AB} = C_{1} + C_{2} = C + C = 2C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.