Q. Number of electric lines of force from 0.5 C if positive charge in a dielectric medium of constant 10 is
A) $5.65 \times 10^{9}$
B) $1.13 \times 10^{11}$
C) $9 \times 10^{9}$
D) $8.85 \times 10^{- 12}$
Explanation
(a) $\phi_{E} = \frac{q}{K\varepsilon_{0}} = \frac{0.5}{10 \times 8.85 \times 10^{12}} = 5.65 \times 10^{9}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.