Q. A technician has only two capacitors. By using these singly, in series or in parallel he can obtain capacitances of $3\ \mu$F,$\ 4\ \mu$F,$\ 12\ \mu$F and $\ 16\ \mu$F. The capacitances of these capacitors are
A) $6\ \mu F\ and\ 10\ \mu F$
B) $4\ \mu F\ and\ 12\ \mu F$
C) $7\ \mu F\ and\ 9\ \mu F$
D) $4\ \mu F\ and\ 16\ \mu F$
Explanation
(b) Here, $C_{s} = \frac{C_{1}C_{2}}{C_{1} + C_{2}} = 3\mu\ F$
And $C_{p} = C_{1} + C_{2} = 16\mu\ F$
Solve to get, $C_{1} = 4\mu\ F\ and\ C_{2} = 12\mu\ F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.