(d) Here, electric potential $V = 3x^{2}$ Electric field, $E = - \frac{\partial V}{\partial x}$ $= - \frac{\partial}{\partial x}\left( 3x^{2} \right) = - 6x\ $ $\therefore E_{(2,\ 0,1)} = - 12Vm^{- 1}$
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Ph.D. in Physics with 19+ years of teaching experience.