Q. Two charges -10C and +10 C are placed 10 cm apart. Potential at the centre of the line joining the two charges is
A) Zero
B) 2 V
C) -2 V
D) None of these
Explanation
(a) $V = \frac{\sum_{}^{}q}{4\pi\varepsilon_{0}r} = \frac{- 10 + 10}{4\pi\varepsilon_{0}r} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.