Q. A dielectric slab is inserted between the plates of an isolated charged capacitor. Which of the following quantities remain unchanged?

A) The charge on the capacitor
B) The stored energy in the capacitor
C) The potential difference between the plates
D) The electric field in the capacitor
Explanation

(a) If a dielectric slab is inserted between the plates of a charged capacitor, the intensity of electric field potential difference of capacitor and the energy stored all reduce to $\frac{1}{K}$ times and capacity of the capacitor increases $K$ times. But the charge on the capacitor remains unchanged.
Here, $K$ is the dielectric constant of dielectric.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.