An electric charge $10^{- 3}\mu C$ is placed at the origin (0, 0) of X-Y coordinate system. Two points A and B are situated at $\left( \sqrt{2},\sqrt{2} \right)and\ (2,0)$respectively. The potential difference between the points A and B will be

Question

Dr. Abubacker · Accepted Answer

(b) Potential at $A$ due to charge at $O$
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$V_{A} = \frac{1}{4\pi\varepsilon_{0}}\frac{\left( 10^{- 3} \right)}{OA}$
$= \frac{1}{4\pi\varepsilon_{0}}.\frac{\left( 10^{- 3} \right)}{\sqrt{\left( \sqrt{2} \right)^{2} + \left( \sqrt{2} \right)^{2}}}$
Potential at $B$ due to charge at O
$V_{B} = \frac{1}{4\pi\varepsilon_{0}}.\frac{\left( 10^{- 3} \right)}{OB}$
$= \frac{1}{4\pi\varepsilon_{0}}.\frac{\left( 10^{- 3} \right)}{2}$
So,
$V_{A} - V_{B} = 0\ $

Q. An electric charge $10^{- 3}\mu C$ is placed at the origin (0, 0) of X-Y coordinate system. Two points A and B are situated at $\left( \sqrt{2},\sqrt{2} \right)and\ (2,0)$respectively. The potential difference between the points A and B will be

Explanation

Reviewed by Dr. Abubacker

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