(a) By definition $\int_{l = \infty}^{l = 0}{- E.dl = V,\ \ }$ the potential at the centre of ring and $V = \frac{1}{4\pi\varepsilon_{0}}.\frac{Q}{R} = \frac{9 \times 10^{9} \times 1.11 \times 10^{- 10}}{0.5} = 2V$
Hence value of given line integral is 2 V.