(b) The two charges form an electric dipole and for this dipole any point on $y$-axis is at the equatorial line. Hence, $\overrightarrow{E}$ at all point on y-axis will be in a direction opposite to $\overrightarrow{p}$ and $\overrightarrow{p}$ is along negative $x$-axis. So $\overrightarrow{E}\ $is along positive $x\ $–axis , $ie,$ along $\widehat{\dot{i}}\ .$