Q. On moving a charge of 20 C by 2cm, 2J of work is done, then the potential difference between the points is
A) 0.1V
B) 8V
C) 2V
D) 0.5V
Explanation
(a) Potential difference between two points in a electric fields is,
$V_{A} - V_{B} = \frac{W}{q_{0}}$
Where $W$ is work done by moving charge $q_{0}$ from point $A\ to\ B.$
So,
$V_{A} - V_{B} = \frac{2}{20}$
(Here $W = 2,\ q_{0} = 20C$)=0.1V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.