(b) $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 = \frac{\frac{16}{5}C}{\frac{16}{5} + C}$ or $\ \ \ \ \ \ C = 48\mu F$ [image:2_image143.emf]
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.