Q. In a region of space having a uniform electric field E, a hemispherical bowl of radius $r$ is placed. The electric flux $\phi$ through the bowl is
A) $2\pi rE$
B) $4\pi r^{2}E$
C) $2\pi r^{2}E$
D) $\pi r^{2}E$
Explanation
(c) $\phi = E(ds)\cos{\theta = E\left( 2\pi r^{2} \right)\cos{0^{0} = 2}}\pi r^{2}E$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.