Q. If a charged spherical conductor of radius 10 cm has potential V at a point distant 5cm from its centre, then the potential at a point distant 15 cm from the centre will be
A) $\frac{1}{3}V$
B) $\frac{2}{3}V$
C) $\frac{3}{2}V$
D) 3V
Explanation
(b) Potential inside the sphere will be same as that on its surface
$ie,\ \ \ V = V_{surface} = \frac{q}{10}stat - volt$
$V_{out} = \frac{q}{15}stat - volt\ $
$\therefore\frac{V_{out}}{V} = \frac{2}{3}$
$\Longrightarrow V_{out} = \frac{2}{3}V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.