Q. The electric flux for Gaussian surface A that encloses the charged particles in free space. (Given, $q_{1} = - 14\ nC,q_{2} = 78.85\ nC,\ q_{3} = - 56\ nC$)
A) $10^{3}Nm^{2}C^{- 1}$
B) $10^{3}CN^{- 1}m^{- 2}$
C) ${6.32}^{\ } \times 10^{3}\ Nm^{2}C^{- 1}$
D) ${6.32}^{\ } \times 10^{3}\ CN\ ^{- 1}m^{- 2}$
Explanation
(a) Total charge enclosed in surface $A\ $is
$Q = \left( q_{1} + q_{2} + q_{3} \right) = ( - 14 + 78.85 - 56)nC$
$\phi = \frac{Q}{\varepsilon_{0}} = \frac{8.85 \times 10^{- 9}}{8.85 \times 10^{- 12}} = 10^{3\ }Nm^{3}C^{- 1}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.