Q. Taking earth to be a metallic spheres, its capacity will approximately be
A) $6.4 \times 10^{6}$F
B) 700 F
C) 711 $\mu$F
D) 700 pF
Explanation
(c) $C = 4\varepsilon_{0}R,\ \ $where $R = 6.4 \times 10^{6}$ m
$= \frac{6.4 \times 10^{6}}{9 \times 10^{9}} = 711\mu\ F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.