Q. In the circuit shown below, the power developed in the $6\Omega$ resistor is 6 watt. The power in watts developed in the $4\Omega$ resistor is

A) 16
B) 9
C) 6
D) 4
Explanation

(b) $P = \frac{V^{2}}{R} \Rightarrow \frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}} \Rightarrow \frac{6}{P_{2}} = \frac{4}{6} = \frac{2}{3} \Rightarrow P_{2} = 9\ W$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.