(b) $A = \pi r^{2} = \frac{\rho l}{R}or\ r = \left( \frac{\rho l}{\pi R} \right)^{1/2}\ $ $r = \left( \frac{1.7 \times 10^{- 8} \times 0.5}{3.14 \times 2} \right)^{1/2} = 0.367\ mm$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.