Q. An electron (charge $= 1.6 \times 10^{- 19}coulomb$) is moving in a circle of radius $5.1 \times 10^{- 11}m$ at a frequency of $6.8 \times 10^{15}\ revolutions/sec.$ The equivalent current is approximately
A) $5.1 \times 10^{- 3}amp$
B) $6.8 \times 10^{- 3}amp$
C) $1.1 \times 10^{- 3}amp$
D) $2.2 \times 10^{- 3}amp$
Explanation
(c) $i = ev = 1.6 \times 10^{- 19} \times 6.8 \times 10^{15} = 1.1 \times 10^{- 3}amp$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.