Q. A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
A) Doubled
B) Four times
C) One-fourth
D) Halved
Explanation
(a) $\ \ \ \ \ H_{1} = \frac{V^{2}}{R}t$
$\ \ \ \ \ H_{2} = \frac{V^{2}}{R/2}\ t$
$\therefore\ \frac{H_{2}}{H_{1}} = 2$
$\Rightarrow H_{2} = 2H_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.