Q. The current in the given circuit is

A) 0.3A
B) 0.4A
C) 0.1A
D) 0.2A
Explanation

(c) We know that when current flow is same then resistors are connected in series, hence resultant resistance is
$R^{'} = R_{1} + R_{2} = 10\Omega + 20\Omega = 30\Omega$
Also since, cell are connected in opposite directions, the resultant emf is
$E = E_{1} - E_{2} = 5V - 2V = 3V$
From Ohm’s law $E = iR$
$\therefore\ \ \ i = \frac{E}{R} = \frac{3}{30} = 0.1A$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.