Q. The internal resistance of a cell of e.m.f. $12V$ is $5 \times 10^{- 2}\Omega.$ It is connected across an unknown resistance. Voltage across the cell, when a current of $60\ A$ is drawn from it, is
A) $15\ V$
B) $12\ V$
C) $9\ V$
D) $6\ V$
Explanation
(c) $V = E - ir = 12 - 60 \times 5 \times 10^{- 2} = 9V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.