Q. Figure shows a network of eight resistors, each equal to 2$\ \Omega$, connected to a 3V battery of negligible internal resistance. The current $I$ in the circuit is
A) 0.25A
B) 0.50A
C) 0.75A
D) 1.0A
Explanation
(d) The resistance AB, BC and CD in series. The total resistance is
$R_{1} = 2 + 2 + 2 = 6\Omega$
The resistance AE, EF and FD in series. The total resistance is
$R_{2} = 2 + 2 + 2 = 6\Omega$
The resistance BE and CF are in effective
∵ $R_{1}$and$\ R_{2}$ are in parallel
∴ The total resistance
$R = \frac{6 \times 6}{6 + 6} = 3\Omega$
The current in the circuit
$I = \frac{V}{R} = \frac{3}{3} = 1.0A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.