Q. The internal resistance of a cell of emf 2 V is $0.1\Omega$. It is connected to a resistance of $3.9\Omega\ $. The potential difference across is
A) 0.5 V
B) 1.9 V
C) 1.95 V
D) 2 V
Explanation
(c) $i = \frac{E}{R + r} = \frac{2}{3.9 + 0.1} = 0.5;$
$V = E - ir = 2 - 0.5 \times 0.1 = 1.95V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.