Q. If nearly $10^{5}$C liberate 1 g equivalent of aluminium, then the amount of aluminium (equivalent weight g) deposited through electrolysis in 20 min by a current of 50 A will be
A) 0.09 g
B) 0.6 g
C) 5.4 g
D) 10.8 g
Explanation
(c) $m = zit$
$9 = z \times 10^{5} \Rightarrow z = \frac{9}{10^{5}}g\ C^{- 1}$
$\therefore m = zit = 9 \times 10^{- 5} \times 50 \times (20 \times 60) =$5.4 g.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.