(b) From the given circuit $V_{A} - (6 \times 2) - 12 - (9 \times 2) + 4 - (5 \times 2) = V_{B}$ Or $V_{A} - 12 - 12 - 18 + 4 - 10 = V_{B}$ Or $V_{A} - V_{B} =$48 volt
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.