(b) $P = Vi \Rightarrow i = \frac{2.2 \times 10^{3}}{22000} = \frac{1}{10}A$ $Now\ loss\ of\ power = i^{2}R = \left( \frac{1}{10} \right)^{2} \times 100 = 1\ W$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.