Q. In the circuit shown, the heat produced in the $5\Omega$ resistor due to current flowing in it is $10\ cal - s^{- 1}$. The heat generated in $\ \Omega$ resistor is
A) 1 $cal - s^{- 1}$
B) 2$\ cal - s^{- 1}$
C) 3$\ cal - s^{- 1}$
D) 4$\ cal - s^{- 1}$
Explanation
(b) From the figure
$10I_{1} = 5I_{2}\ \ \ \ I_{2} = 2I_{1}$ ….(i)
Heat produced in resistance
${\ I}_{2}^{2}R = I_{2}^{2} \times 5$
$\therefore \times 5 = 10\ cals^{- 1}$ ….(ii)
From Eqs. (i) and (ii) ,we have
$I_{1} = \frac{I_{2}}{2} = \frac{\sqrt{2}}{2} = \frac{1}{\sqrt{2}}$ A
Hence, heat produced in resistance of 4$\Omega$
$I_{2}^{2} \times 4 = \frac{1}{2} \times 4 = 2\ cals^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.