Q. The magnitude and direction of the current in the circuit shown will be
A) $7/3A$ from $a$ to $b$ through $e$
B) $7/3A$ from $b$ to $a$ through $e$
C) $1A$ from $b$ to $a$ through $e$
D) $1A$ from $a$ to $b$ through $e$
Explanation
(d) Since $E_{1}(10V) > E_{2}(4V)$
So current in the circuit will be clockwise
Applying Kirchhoff’s voltage law
$- 1 \times i + 10 - 4 - 2 \times i - 3i = 0 \Rightarrow i = 1A(a\ to\ b\ via\ e)$
$\therefore$ Current $= \frac{V}{R} = \frac{10 - 4}{6} = 1.0\ ampere$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.