Q. The resistance of a galvanometer is $90\ ohm.$ If only 10 percent of the main current may flow through the galvanometer, in which way and of what value, a resistor is to be used
A) $10\ ohm$ in series
B) $10\ ohm$ in parallel
C) $810\ ohm$ in series
D) $810\ ohm$ in parallel
Explanation
(b) $\because i_{g} = 10\%$ of $i = \frac{i}{10} \Rightarrow S = \frac{G}{(n - 1)} = \frac{90}{(10 - 1)} = 10\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.