Q. The length of the wire is doubled. Its conductance will be
A) Unchanged
B) Halved
C) Quadrupled
D) 1/4 of the original value
Explanation
(b) Conductance $C = \frac{1}{R} = \frac{A}{\rho l} \Rightarrow C \propto \frac{1}{l}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.