Q. In the given figure, equivalent resistance between $A$ and $B$ will be
A) $\frac{14}{3}\Omega$
B) $\frac{3}{14}\Omega$
C) $\frac{9}{14}\Omega$
D) $\frac{14}{9}\Omega$
Explanation
(a) The given circuit is a balanced Wheatstone bridge, hence it can be redrawn as follows
$\Rightarrow R_{eq} = \frac{7 \times 14}{(7 + 14)} = \frac{14}{3}\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.