Q. If $V_{AB} = 4V$ in the given figure, then resistance $X$ will be
A) $5\ \Omega$
B) $10\ \Omega$
C) $15\ \Omega$
D) $20\ \Omega$
Explanation
(d) $V_{AB} = 4 = \frac{5X + 2 \times 10}{X + 10} \Rightarrow X = 20\Omega,\ \left\lbrack v = \frac{E_{2}r_{1} + E_{1}r_{2}}{r_{1} + r_{2}} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.