(b) Mass of water $= volume \times density$
$= 1000 \times 1 =$ 1000 g.
Heat taken by water $= mc\ \mathrm{\Delta}\theta$
$= 1000 \times 1(37 - 22)$ cal
$= 1000 \times 15 \times 4.2$ J
Power of geyser$= \frac{energy\ spent}{time}$
$\ = \frac{1000 \times 15 \times 4.2}{60}1050$ W.