Q. The relation between Faraday constant $(F),$ chemical equivalent $(E)$ and electrochemical equivalent $(Z)$ is
A) $F = EZ$
B) $F = \frac{Z}{E}$
C) $F = \frac{E}{Z}$
D) $F = \frac{E}{Z^{2}}$
Explanation
The correct answer is Option C: $F = \frac{E}{Z}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.