The maximum current that can be measured by a galvanometer of resistance 40$\Omega$ is 10mA. It is converted into a voltmeter that can read upto 50V. The resistance to be connected is series with the galvanometer (in ohm) is

Question

Dr. Abubacker · Accepted Answer

(d) To convert galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer is
$R = \frac{V}{I_{g}} - G$
$= \frac{50}{10 	imes 10^{- 3}} - 40$
$= 5000 - 40 = 4960\Omega$

Q. The maximum current that can be measured by a galvanometer of resistance 40$\Omega$ is 10mA. It is converted into a voltmeter that can read upto 50V. The resistance to be connected is series with the galvanometer (in ohm) is

Explanation

Reviewed by Dr. Abubacker

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